2x^2=0.32

Solution for 2x^2=0.32 equation:

2x^2=0.32

We move all terms to the left:

2x^2-(0.32)=0

We add all the numbers together, and all the variables

2x^2-0.32=0

a = 2; b = 0; c = -0.32;
Δ = b2-4ac
Δ = 02-4·2·(-0.32)
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.56}}{2*2}=\frac{0-\sqrt{2.56}}{4}
=-\frac{\sqrt{}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.56}}{2*2}=\frac{0+\sqrt{2.56}}{4}
=\frac{\sqrt{}}{4}
$